Answer:
612.2 m
Explanation:
The work needed to lift the object is equal to its increase in gravitational potential energy:
[tex]W=\Delta U=mg \Delta h[/tex] (1)
where
m = 1.0 kg is the mass
g = 9.8 m/s^2
[tex]\Delta h[/tex] is the vertical distance
The power provided is
[tex]P=0.10 kW = 100 W[/tex]
In one minute (t = 1 min = 60 s), the work provided is
[tex]W=Pt=(100 W)(60 s)=6000 J[/tex]
Substituting this into (1) and solving for [tex]\Delta h[/tex], we find
[tex]\Delta h=\frac{W}{mg}=\frac{6000 J}{(1.0 kg)(9.8 m/s^2)}=612.2 m[/tex]
