Answer:
[tex](x',y')-->(x-3,y-2)[/tex]
Step-by-step explanation:
Notice that we can get from the x-coordinate of A, 1, to the x-coordinte of A', -2, by subtracting 3 from the x-coordinate of A. More formaly:
[tex]1+a=-2[/tex]
[tex]a=-2-1[/tex]
[tex]a=-3[/tex]
Similarly, we can get from the y-coordinate of A, 5, to the y-coordinate of A', 3, by subtracting 2 from the y-coordinte of A. More formaly:
[tex]5+b=3[/tex]
[tex]b=3-5[/tex]
[tex]b=-2[/tex]
Now we now that to get to A' from A, we need to subtract 3 to the x-coordinate of A and subtract 2 to the y-coordinate. Knowing this, we can create the expression to translate any point of the polygon ABCD to create the polygon A'B'C'D':
[tex](x',y')-->(x-3,y-2)[/tex]
