Answer:
Use the quadratic formula
Step-by-step explanation:
Use the quadratic formula
For a quadratic function of the form:
[tex]ax ^ 2 + bx + c[/tex]
Where a, b and c are the real coefficients of the polynomial
Then, for
[tex]2x^2+4x-7=0\\a = 2\\b = 4\\c = -7[/tex]
The solutions are:
[tex]x_1 = \frac{-b+\sqrt{b^2-4ac}}{2a}\\\\x_2 = \frac{-b-\sqrt{b^2-4ac}}{2a}[/tex]
[tex]x_1 = \frac{-4+\sqrt{4^2-4(2)(-7)}}{2(2)}\\\\x_2 = \frac{-4-\sqrt{4^2-4(2)(-7)}}{2(2)}\\\\x_1 = \frac{-2+3\sqrt{2}}{2}\\\\x_2 = \frac{-2-3\sqrt{2}}{2}[/tex]
