Answer:
True
Step-by-step explanation:
To answer this question we must evaluate
y = 0° on both sides of the equation.
For the left side we have:
[tex]sin(0\°) tan(0\°)[/tex]
We know that [tex]tan(0\°) =\frac{sin(0\°)}{cos(0\°)}[/tex]
We know that [tex]cos(0\°) = 1[/tex] and [tex]sin(0\°) = 0[/tex].
Therefore [tex]tan(0\°) = 0[/tex].
Then the left-hand side of the equals is equal to zero.
On the right side we have:
[tex]cos(y)[/tex]
When evaluating [tex]cos(y)[/tex] at [tex]y = 0[/tex]
We have to [tex]cos(0\°) = 1[/tex].
0 ≠ 1
The equation is not satisfied. Therefore y = 0 ° is a counterexample to the equation
