What is the probability of rolling a 5 on the first number cube and rolling a 6 on the second number cube? Assume the number cubes are fair and have six sides. Express your answer as a fraction in simplest form.

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absor201 absor201 · Answer 1 · 2019-04-14T13:43:33+02:00

Answer:

The probability of rolling a 5 on the first number cube and rolling a 6 on the second number cube is 1/36

Step-by-step explanation:

There are total 6 possible outcomes of rolling a six sided fair cube. Therefore, the probability of rolling each number (1,2,3,4,5,6) is fair = 1/6

In this way,

The probability of rolling a 5 on the first number cube = p(A) = 1/6

The probability of rolling a 6 on the second number cube = p(B) = 1/6

The probability of rolling a 5 on the first number cube and rolling a 6 on the second number cube is = p(A) * p(B) = 1/6*1/6 = 1/36

divinegraceonyegbunk divinegraceonyegbunk · Answer 2 · 2021-03-18T23:42:05+01:00

Answer:

1/36

Step-by-step explanation:

The probability of rolling a 5 on the first number cube and rolling a 6 on the second number cube is 1/36

Step-by-step explanation:

There are total 6 possible outcomes of rolling a six sided fair cube. Therefore, the probability of rolling each number (1,2,3,4,5,6) is fair = 1/6

In this way,

The probability of rolling a 5 on the first number cube = p(A) = 1/6

The probability of rolling a 6 on the second number cube = p(B) = 1/6

The probability of rolling a 5 on the first number cube and rolling a 6 on the second number cube is = p(A) * p(B) = 1/6*1/6 = 1/36