Write an equation of each line that passes through the following points in slope-intercept form:
P (4, 1) and Q (3, –5)

help me please

Respuesta :

gmany

Answer:

y = 6x - 23

Step-by-step explanation:

The slope-intercept form of an equation of a line:

[tex]y=mx+b[/tex]

The formula of a slope:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

We have the points P(4, 1) and Q(3, -5). Substitute:

[tex]m=\dfrac{-5-1}{3-4}=\dfrac{-6}{-1}=6[/tex]

The refore we have the equation:

[tex]y=6x+b[/tex]

Put the coordinates of the point P(4, 1) to the equation:

[tex]1=6(4)+b[/tex]

[tex]1=24+b[/tex]          subtract 24 from both sides

[tex]-23=b\to b=-23[/tex]

Finally we have the equation:

[tex]y=6x-23[/tex]