[tex]\bf \textit{lateral area of a cone}\\\\ LA=\pi r\sqrt{r^2+h^2}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3\\ h=3 \end{cases}\implies LA=\pi (3)\sqrt{3^2+3^2} \\\\\\ LA=3\pi \sqrt{2(3^2)}\implies \boxed{LA=9\pi \sqrt{2}} \\\\[-0.35em] ~\dotfill[/tex]
[tex]\bf \textit{total surface area of a cone}\\\\ SA=\pi r\sqrt{r^2+h^2}+\pi r^2~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3\\ h=3 \end{cases}\implies SA=\boxed{9\pi \sqrt{2}}+\pi 3^2 \\\\\\ SA=9\pi \sqrt{2}+9\pi \implies SA\approx 68.26[/tex]
