Respuesta :
Answer:
= 160 mL
Explanation:
The equation for the reaction is;
Ca(OH)2 + 2HNO3 -----> Ca(NO3)2 + 2H2O
Moles of Ca(OH)2 = 0.080 L x 5.00^-3 M
= 0.0004 moles
From the reaction; 2 moles of HNO3 reacts with 1 mole of Ca(OH)2
Thus; moles of HNO3 = 0.0004 Moles × 2
= 0.0008 moles
Volume = moles/ molarity
Therefore; volume of HNO3= 0.0008 Moles/ 5 × 10^-3 M
= 0.16 L or 160 mL
The volume of 5×10⁻³ M HNO₃ needed to titrate 80ml of 5×10⁻³ M ca(oh)2 to the equivalence point is 160mL.
How we calculate volume from moles?
Volume of any solution will be calculated by using moles and molarity as:
Volume = moles / molarity
Given chemical reaction is:
Ca(OH)₂ + 2HNO₃ → Ca(NO₃)₂ + 2H₂O
From the stoichiometry of the reaction it is clear that,
2 mole of HNO₃ = react with 1 mole of Ca(OH)₂
Given volume of Ca(OH)₂ = 80mL = 0.080L
Given molarity of Ca(OH)₂₂ = 5×10⁻³ M
Moles of Ca(OH)₂ = 0.080L x 5×10⁻³M = 0.0004 moles
0.0004 moles of Ca(OH)₂ = react with 2×0.0004 = 0.0008 moles of HNO₃
Given molarity of HNO₃ = 5×10⁻³ M
Volume of HNO₃ = 0.0008moles / 5×10⁻³ M = 0.16L = 160mL
Hence, 160mL of HNO₃ is required.
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