a) zinc
The equation of the photoelectric effect is:
[tex]E=\phi + K[/tex] (1)
where
E is the energy of the incident light
[tex]\phi[/tex] is the work function
[tex]K[/tex] is the maximum kinetic energy of the emitted photoelectrons
Here the wavelength of the incident light is
[tex]\lambda=200 nm = 2\cdot 10^{-7} m[/tex]
so the energy of the light is
[tex]E=\frac{hc}{\lambda}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{2\cdot 10^{-7} m}=9.95\cdot 10^{-19} J[/tex]
Converting into electronvolts,
[tex]E=\frac{9.95\cdot 10^{-19}}{1.6\cdot 10^{-19} J/eV}=6.22 eV[/tex] (2)
The stopping potential is the potential needed to stop the photoelectrons with maximum kinetic energy: so, the electrical potential energy corresponding to the stopping potential (V=1.93 V) must be equal to the maximum kinetic energy of the photoelectrons,
[tex]U=q V = K[/tex]
and since the charge of the electron is
1 q = 1 e
We have
[tex]K=(1 e)(1.93 V)=1.93 eV[/tex] (3)
Combining (1), (2) and (3), we find the work function of the material:
[tex]\phi = E-K=6.22 eV-1.93 eV=4.29 eV[/tex]
So, the cathode is most likely made of zinc, which has a work function of 4.3 eV.
b) The stopping potential does not change
As we said in part A), the stopping potential is proportional to the maximum kinetic energy of the photoelectrons, K.
The intensity of light is proportional to the number of photons that hit the surface of the metal. However, the energy of these photons does not depend on the intensity, but only on the frequency of the light.
Therefore, the energy of the photons (E) does not change when the intensity of light is doubled. Also, the work function [tex]\phi[/tex] does not change: this means that the maximum kinetic energy of the photoelectrons, K, does not change, and so the stopping potential remains the same.
If the intensity of light is doubled, the stopping potential is still 1.93 V.
The term photoelectric effect refers to the fact that electrons are emitted from the surface of a metal when it is irradiated with light of the appropriate frequency.
Now;
Kinetic energy = Energy of photon - work function
Energy of the photon = 6.6 * 10^-34 * 3 * 10^8/200 * 10^-9
= 9.9 * 10^-19 J
For the stopping potential or kinetic energy;
1 ev = 1.6 * 10^-19 J
1.93 eV = 1.93eV * 1.6 * 10^-19 J/1 ev = 3.1 * 10^-19 J
Work function of the metal = 9.9 * 10^-19 J - 3.1 * 10^-19 J
= 6.8 * 10^-19 J or 4.25 eV
The metal is zinc
We know that the stopping potential is independent of the light intensity hence if the intensity of light is doubled, the stopping potential is still 1.93 V.
Learn more about photoelectric effect: https://brainly.com/question/9431503?
