For this case we have the [tex]CO_ {2}[/tex]
It is composed of one atom of carbon and two of oxygen.
The atomic mass of carbon and oxygen, which can be found in a periodic table, are given by:
[tex]C: 12 \frac {g} {mol}\\O: 16 \frac {g} {mol}[/tex]
Then, we find the atomic mass of [tex]CO_{2}[/tex]:
[tex]1 * 12 \frac {g} {mol} = 12 \frac {g} {mol}\\2 * 16 \frac {g} {mol} = 32 \frac {g} {mol}[/tex]
Adding we have:
[tex]44 \frac {g} {mol}[/tex]
To find the percentage of oxygen, we divide the atomic mass of the two oxygen atoms between that of [tex]CO_{2}:[/tex]
[tex]\frac {32} {44} * 100 = 72.73[/tex]%
Thus, the percentage of oxygen is 72.73%
Answer:
72.73%
