Answer:
The period of given function is [tex]Period = 16\pi [/tex]
So, Option B is correct.
Step-by-step explanation:
In this question we need to find the period of the function y= 3 sin x/8
The formula used to find period of function is: [tex]\frac{2\pi }{b}[/tex]
We need to know the value of b.
To find the value of b we compare the standard equation with the equation of function given.
Standard Equation: y = a sin(bx - c) +d
Given Equation: y= 3 sin(x/8)
Comparing we get:
a= 3
b= 1/8
c= 0
d=0
So, we get the value of b i.e 1/8. Putting it in the formula to find period of given function.
[tex]Period = \frac{2\pi }{b}[/tex]
[tex]Period = \frac{2\pi }{\frac{1}{8}}[/tex]
Solving,
[tex]Period = 2\pi *8[/tex]
[tex]Period = 16\pi [/tex]
So, the period of given function is [tex]Period = 16\pi [/tex]
