Answer:
Option B
Step-by-step explanation:
Given
f(x)= (x^2+x-2)/(x^3-1)
For vertical asymptotes we have to put the denominator of the function equal to zero:
x^3-1=0
x^3=1
So,
x=1
As the degree of denominator is greater than the degree of numerator, there will be only horizontal asymptote which will be y=0 because all the y values will be dragged down to the x-axis.
So the horizontal asymptote: y=0
And Vertical asymptote: x =1
