Given the value of cos 50° ? 0.6428, enter the sine of a complementary angle. Use an expression relating trigonometric ratios of complementary angles.

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ANSWER

[tex]\sin(40) \degree = 0.6428[/tex]

EXPLANATION

The sine and cosine ratios are complementary.

This means that:

[tex] \cos(x \degree) = \sin(90 - x) \degree[/tex]

We were given that,

cos(50°)=0.6428

We want to find the sine of the complement of this angle.

[tex] \cos(50\degree) = \sin(90 -5 0) \degree[/tex]

[tex]\cos(50\degree) = \sin(40) \degree[/tex]

This implies that,

[tex] \sin(40) \degree = 0.6428[/tex]