Answer:
If 4a+8b+4c=1, then 16a+16c+32b = 4
Step-by-step explanation:
To answer the question, a rule of three can be raised:
4a + 8b + 4c --------------- 1
16a + 16c + 32b --------- X
X = (16a + 16c + 32b) ÷ (4a + 8b + 4c)
This is equivalent to the division of the two polynomials, 16a + 16c + 32b by 4a + 8b + 4c.
Before dividing we organize the first polynomial,
16a + 16c + 32b = 16a + 32b + 16c
Dividing the two polynimials, we have
16a + 32b + 16c | 4a + 8b + 4c
-16a - 32b - 16c 4
= 0 =
The exact quotient is 4, since the residue is 0
Hope this hepls!
