Answer:
The surface area is [tex]156\ in^{2}[/tex]
Step-by-step explanation:
we know that
The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces
so
[tex]SA=b^{2}+4[\frac{1}{2}(b)(l)][/tex]
where
[tex]b=6\ in[/tex]
[tex]l=10\ in[/tex] -----> the slant height
substitute the values
[tex]SA=6^{2}+4[\frac{1}{2}(6)(10)][/tex]
[tex]SA=156\ in^{2}[/tex]
