Respuesta :

frika

Answer:

x+3

Step-by-step explanation:

1. Use formula for the difference of squares:

[tex]a^2-b^2=(a-b)(a+b)[/tex]

to factor

[tex]x^2-9=(x-3)(x+3).[/tex]

2. Factor [tex]x^2+8x+15:[/tex]

[tex]x^2+8x+15=x^2+3x+5x+15=x(x+3)+5(x+3)=(x+3)(x+5).[/tex]

Now you can see that [tex]x+3[/tex] is the common factor.

Answer:

x + 3

Step-by-step explanation:

x² - 9 ← is a difference of squares and factors as

x² - 9 = (x - 3)(x + 3)

To factor x² + 8x + 15

Consider the factors of the constant term (+ 15) which sum to give the coefficient of the x- term (+ 8)

The factors are + 5 and + 3, since

5 × 3 = 15 and 5 + 3 = 8, thus

x² + 8x + 15 = (x + 5)(x + 3)

Thus the factor (x + 3) is common to both

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