Respuesta :

r3t40

[tex]

3-2z=\frac{1}{10} \\

30-20z=1\\

-20z=-29 \\

z=\frac{-29}{-20} \Longrightarrow z=\boxed{1.45}

[/tex]

For this case we have the following equation:

[tex]3-2z = \frac {1} {10}[/tex]

We must find the value of z that represents the solution of the equation:

We follow the steps below:

We multiply by 10 on both sides of the equation:

[tex]10 (3-2z) = 1[/tex]

We apply distributive property to the terms of parentheses;

[tex]30-20z = 1[/tex]

We subtract 30 from both sides of the equation:

[tex]-20z = 1-30\\-20z = -29[/tex]

We divide between -20 on both sides of the equation:

[tex]z = \frac {-29} {- 20}\\z = \frac {29} {20}\\z = 1.45[/tex]

If we substitute the value of z in the original equation, equality is satisfied.

Answer:

[tex]z = 1.45[/tex]