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A scuba diver 25.0m below the sea surface inhales 75.0mL of compressed air in a scuba tank at a pressure of 3.50atm and a temperature of 5.0C. What is the pressure of the air in the lungs if the gas expands to 215.0mL at the body temperature of 37.2C?

Respuesta :

Answer:

Explanation:

Use the combined gas law

P(V)/T=P(V)/T

P is pressure

V is volume

T is temperature

3.5 atm(75 mL)/(5 C)=P(215 mL)=(37.2 C)

yu can change celcius to kelvin by adding 273.

And then just solve the equation

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