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The Hubble telescope’s orbit is 5.6 × 105 meters above Earth’s surface. The telescope has a mass of 1.1 × 104 kilograms. Earth exerts a gravitational force of 9.1 × 104 newtons on the telescope. The magnitude of Earth’s gravitational field strength at this location is

Respuesta :

AL2006

Gravitational force = 9.1 x 10⁴ newtons

Mass  =  1.1 x 10⁴ kilograms

Gravitational field strength =  9.1 x 10⁴ newtons / 1.1 x 10⁴ kilograms

                                      =  ( 9.1 / 1.1)  (newton / kilogram)

                                       =   8.3 newton/kg

                                       or  8.3 m/s² .

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