CAN SOMEONE HELP ME FAST. thanks

Y= 3x + 2 Is the equation of a straight line graph. Where does it cross the y-axis? Also can you tell me how to work it out?

Respuesta :

The equation is a straight line on the graph because it is in slope-intercept form. (y=mx+b) It crosses the x-axis at (0,2) since if you substitute 0 for x, it comes out as 2. (3*0=0, 0+2) The y-intercept is the y-value when x is 0.
AL2006

That equation is in what's called "standard form".  It's the form where
'y' is all alone on one side and everything else is on the other side.
The reason it's called "standard form" is because when the equation
is written that way, you can just LOOK at it and tell so much about it.

           Y  =  (the number next to 'x') X  +  (a number all alone) .

When the equation is written like this:

-- If the 'x' has no power written, like x² or x³ , then
you know the graph of the equation is a straight line.

-- "The number next to x" is the slope of the line on the graph.
     If the number is positive, the line slopes up.
     If the number is negative, the line slopes down.

-- "The number all alone" is the y-intercept of the graph ...
     the point where the line crosses the y-axis.

Your equation is          Y = 3 x  +  2 .

-- The equation is written in 'standard form'.

-- The 'x' has no exponent written, so its exponent is ' 1 ',
     and you know the graph is a straight line.

-- The number next to 'x' is  3 . 
   The line on the graph slopes up, and its slope is  3 .

-- The number all alone is  2 .
   The line on the graph crosses the y-axis at the point  y=2