Respuesta :

kudzordzifrancis

ANSWER

20 units.

EXPLANATION

We want to find the distance between (-8,-8) and (4,8).

We use the distance formula:

[tex]d = \sqrt{ {(x_2-x_1)}^{2} + {(y_2-y_1)}^{2} } [/tex]

We substitute the points into the formula to get:

[tex]d = \sqrt{ {(4 - - 8)}^{2} + {(8 - - 8)}^{2} } [/tex]

We simplify to get;

[tex]d = \sqrt{ {(12)}^{2} + {(16)}^{2} } [/tex]

[tex]d = \sqrt{144+ 256} [/tex]

[tex]d = \sqrt{400} [/tex]

[tex]d = 20[/tex]

The distance between the two points is 20 units.

imlittlestar

Answer:

Distance = 20 units

Step-by-step explanation:

Points to remember

Distance formula

Length of a line segment with end points (x1, y1) and (x2, y2) is given by,

Distance = √[(x2 - x1)² + (y2 - y1)²]

To find the distance between give 2 points

Here (x1, y1) = (-8, -8)  and (x2, y2) = (4, 8)

Distance = √[(x2 - x1)² + (y2 - y1)²]

 = √[(4 - -8)² + (8 - -8)²]

 = √[(4 + 8)² + (8 + 8)²]

 = √[12² + 16²] =  √[144 + 256)

  =  √400 = 20

Therefore distance = 20 units

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