Answer:
Option C. 1,493
Step-by-step explanation:
If the deer population in a region is expected to decline 1.1% from 2010 to 2020. Assuming this continued, we can say that the deer population decreases 1.1% each ten years.
From 2010 to 2060 there are 50 years. If the deer population decreases 1.1% each ten years, then it will decrease 5.5% in 50 years.
If the population in 2010 was 1,578. Then, the population in 2060 is going to be:
Using the rule of three:
If 1578 ----------------> Represents 100%
X <----------------- 5.5%
X = (5.5%x1578)/100% = 86.79 ≈ 87
Then the total population in 2060 is: 1578 - 87 = 1491
None of the answers equal to 1491. That's why I assume the correct answer must be Option C. 1,493. Given that it's the closest answer!
Answer:
The population would be 1,493.
Step-by-step explanation:
Given,
The initial population, P = 1,578, ( In 2010 )
Also, the decline rate per 10 years, r = 1.1 %,
And, the number of the periods of 10 years since, 2010 to 2060, n = 5,
Hence, the population in 2060 would be,
[tex]A=P(1-\frac{r}{100})^n[/tex]
[tex]=1578(1-\frac{1.1}{100})^5[/tex]
[tex]=1493.09849208\approx 1493[/tex]
Option third is correct.
