Answer:
D. 597
Step-by-step explanation:
This question is on finding the inverse of a 3×3 matrix
The general formula of finding a 3×3 matrix is given by;
[tex]A=\left[\begin{array}{ccc}a&b&c\\d&e&f\\g&h&i\end{array}\right] = a.D\left[\begin{array}{ccc}e&f&\\h&i&\\&&\end{array}\right] -b.D\left[\begin{array}{ccc}d&f&\\g&i&\\&&\end{array}\right] + c.D\left[\begin{array}{ccc}d&e&\\g&h&\\&&\end{array}\right][/tex]
where D is determinant
Given ;
[tex]k=\left[\begin{array}{ccc}14&-13&0\\3&8&-1\\-10&-2&5\end{array}\right] then ;\\\\\\\\ =14 D \left[\begin{array}{ccc}8&-1&\\-2&5&\\&&\end{array}\right] -13D\left[\begin{array}{ccc}3&-1&\\-10&5&\\&&\end{array}\right] + 0.D\left[\begin{array}{ccc}3&8&\\-10&-2&\\&&\end{array}\right][/tex]
= 14 [ 40-2] - -13[ 15-10] + 0
=14 [38] - [-65]+0
=532+65
=597
