Respuesta :

[tex]\bf \textit{area of a sector of a circle}\\\\ A=\cfrac{\pi \theta r^2}{360}~~ \begin{cases} r=&radius\\ \theta =&angle~in\\ &degrees\\ \cline{1-2} r=&6\\ \theta =&87 \end{cases}\implies A=\cfrac{\pi (87)(6)^2}{360}\implies A=\cfrac{87\pi }{10} \\\\\\ A\approx 27.332\implies \stackrel{\textit{rounded up}}{A=27.3}[/tex]