Answer:
(-2,-4)
Step-by-step explanation:
in this exercise I have the formula of the parable expressed as:
[tex]y=ax^{2} +bx+c[/tex]
I can write it in its "vertex form"
[tex]y=a(x-d)^{2} +e[/tex] being (d,e) the coordinates of the vertex of said parabola.
by clearing the equation I can see that [tex]d=\frac{-b}{2a}[/tex] so I substitute[tex]d=-\frac{4}{2*1} =-2[/tex]
Now taking d as the value for the x axis of the vertex coordinate, I substitute d in x, in the initial equation
[tex]y=x^{2} +4x =(-2)^{2}+4(-2)=4-8=-4[/tex]
So finally, I have the coordinates of the vertex of the parabola are (-2,-4)
Done
