Answer:
Option A is correct.
Step-by-step explanation:
Zeros at -8, -1 and 3 means these are the factors of the polynomial.
x=-8, x=-1 and x =3
It can be written as:
x+8=0, x+1=0 and x-3=0
Factors can be written as:
(x+8)(x+1)(x-3)=0
Multiplying the first two terms and then their product with third terms:
[tex](x(x+1) +8(x+1))(x-3) =0\\(x^2+x+8x+8)(x-3)=0\\Adding\,\, like\,\, terms\,\,:\,\,\\(x^2+9x+8)(x-3) =0\\x(x^2+9x+8) -3(x^2+9x+8)=0\\x^3+9x^2+8x-3x^2-27x-24=0\\Adding\,\, like\,\, terms\,\,:\,\,\\x^3+9x^2-3x^2+8x-27x-24=0\\x^3+6x^2-19x-24=0\\or\,\,f(x) = x^3+6x^2-19x-24[/tex]
So, Option A is correct.
