Respuesta :

carlosego

For this case we must solve the following inequality:

[tex]8x-5 \geq27[/tex]

We add 5 to both sides of the inequality:

[tex]8x\geq27 + 5\\8x\geq32[/tex]

DIviding between 8 on both sides of the equation:

[tex]x \geq \frac {32} {8}\\x \geq4[/tex]

Thus, the solution is given by all the numbers greater than or equal to 4

Answer:

[tex]x \geq4[/tex]

luisejr77

Answer: [tex]x\geq4[/tex]

Step-by-step explanation:

Given the inequality [tex]8x-5\geq27[/tex], you need to solve for the variable "x".

You must follow these steps to solve for the variable "x":

- First, you need to add 5 to both sides of the inequality. Then:

[tex]8x-5+(5)\geq27+(5)\\\\8x\geq32[/tex]

- And finally, you need to divide both sides of the inequality by 8.

Therefore, you get:

[tex]\frac{8x}{8}\geq\frac{32}{8}\\\\x\geq4[/tex]

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