Respuesta :
If you are trying to find the molarity of this solution you first need to find the number of moles of sodium chloride that are present in the 0.5g sample. To do this you need to divide the mass of sodium chloride (0.5g) by its molar mass (58.45g/mol) to get 0.00855mol of sodium chloride. Then you divide the number of moles (0.00855mol) by the volume of solution (0.05L) to get 0.171M (The units for molarity is mol/L). Therefore the solution has a concentration of 0.171M.
I hope this helps. Let me know in the comments if anything was unclear or if you were asking a different question.
I hope this helps. Let me know in the comments if anything was unclear or if you were asking a different question.
The concentration of the solution has been 0.17 M.
The molarity has been defined as the moles of solute that has been dissolved in a liter of solution. The molarity of the solution has been expressed as:
[tex]\rm Molarity=\dfrac{Mass}{Molar\;mass}\;\times\;\dfrac{1}{Volume\;(L)}[/tex]
Computation for Molarity of the solution
The molar mass of sodium chloride solution has been 58.5 g/mol.
The given mass of NaCl in the solution has been 0.5 grams.
The volume of NaCl solution has been 0.05 L.
Substituting the values for molarity of the solution:
[tex]\rm Molarity=\dfrac{0.5}{58.5}\;\times\;\dfrac{1}{0.05\;L}\\\\Molarity=0.17 M[/tex]
The concentration of the solution has been 0.17 M. The solution has been prepared by dissolving 0.5 g NaCl in minimal water, and makeup the volume to 0.05 L.
Learn more about molarity, here:
https://brainly.com/question/12127540
