Answer:
[tex]\large\boxed{\text{the sloe}\ m=\dfrac{2}{3}}[/tex]
Step-by-step explanation:
[tex]\text{Let}\\\\k:y=m_1x+b_1\\\\l:y=m_2x+b_2\\\\l\ \parallel\ k\iff m_1=m_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}[/tex]
[tex]\text{We have the slope}\ m_1=\dfrac{2}{5}.\\\\\text{The slope of parallel line is the same:}\ m_2=\dfrac{2}{5}[/tex]
