Explanation:
It is given that,
Radius of earth, r = 6371 km
An earth satellite moves in a circular orbit above the Earth's surface, d = 561 km
So, radius of satellite, R = 6371 km + 561 km = 6932 × 10³ m
Time taken, t = 95.68 min = 5740.8 sec
(a) Speed of the satellite is given by :
[tex]v=\dfrac{d}{t}[/tex]
d = distance covered
For circular path, d = 2πR
[tex]v=\dfrac{2\pi \times 6932\times 10^3\ m}{5740.8\ sec}[/tex]
v = 7586.92 m/s
(b) Centripetal acceleration is given by :
[tex]a=\dfrac{v^2}{R}[/tex]
[tex]a=\dfrac{(7586.92\ m/s)^2}{6932\times 10^3\ m}[/tex]
[tex]a=8.3\ m/s^2[/tex]
Hence, this is the required solution.
