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A series circuit that is connected to a 50 V, 60 Hz source is made up of 25 ohm resistor, capacite wieh X= 18 ohms, and inductor with X 24 ohms, what is the circuit impedance? a. 25.70 b. 29.2Q 32.4Q c. d. 35.90 5

Respuesta :

Answer:

the impedance of the circuit is 25.7 ohms.

Explanation:

It is given that,

Voltage, V = 50 volts

Frequency, f = 60 Hz

Resistance, R = 25 ohms

Capacitive resistance, [tex]X_C=18\ ohms[/tex]

Inductive resistance, [tex]X_L=24\ ohms[/tex]

We need to find the impedance of the circuit. It is given by :

[tex]Z=\sqrt{R^2+(X_L-X_C)^2}[/tex]

[tex]Z=\sqrt{25^2+(24-18)^2}[/tex]

Z = 25.7 ohms

So, the impedance of the circuit is 25.7 ohms. Hence, this is the required solution.

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