Answer:
The current flows in the second wire is [tex]1.3\times10^{10}\ A[/tex]
Explanation:
Given that,
Upward current = 24 A
Force per unit length[tex]\dfrac{F}{l} =88\times10^{4}\ N/m [/tex]
Distance = 7.0 cm
We need to calculate the current in second wire
Using formula of magnetic force
[tex]F=ILB[/tex]
[tex]\dfrac{F}{l}=\dfrac{\mu I_{1}I_{2}}{2\pi r}[/tex]
Where,
[tex]\dfrac{F}{l}[/tex]=force per unit length
I₁= current in first wire
I₂=current in second wire
r = distance between the wires
Put the value into the formula
[tex]88\times10^{4}=\dfrac{4\pi\times10^{-7}\times24\times I_{2}}{2\pi \times7\times10^{-2}}[/tex]
[tex]I_{2}=\dfrac{88\times10^{4}\times7\times10^{-2}}{2\times\times10^{-7}\times24}[/tex]
[tex]I_{2}=1.3\times10^{10}\ A[/tex]
Hence, The current flows in the second wire is [tex]1.3\times10^{10}\ A[/tex]
