Answer:
22.47 %
Explanation:
v 1 = 328 m/s, v 2 = 363 m/s
We know that the velocity of a wave in a stretch string is directly proportional to the square root of the tension in the string.
[tex]\frac{v1}{v2}=\sqrt{\frac{T1}{T2}}[/tex]
[tex]\frac{T1}{T2}=\left ( \frac{328}{363} \right )^{2}[/tex]
[tex]\frac{T1}{T2}=0.8165[/tex]
Percentage increase in the tension
[tex]\frac{T2 - T1}{T1}\times 100 = \left (\frac{T2}{T1}-1 \right )\times 100[/tex]
= \left ( \frac{1}{0.8165}-1 \right )\times 100
= 22.47 %
