Step-by-step explanation:
We are asked to graph the equation of an ellipse given by [tex]\frac{x^2}{36}+\frac{y^2}{49}=1[/tex].
We know that standard from of an ellipse [tex]\frac{x^2}{a^2}+\frac{y^2}{b^1}=1[/tex], when [tex]a>b[/tex], then the ellipse will be horizontal and when [tex]a<b[/tex], then the ellipse will be vertical.
We can rewrite our given ellipse as: [tex]\frac{x^2}{6^2}+\frac{y^2}{7^2}=1[/tex].
Upon looking at our given ellipse we can see that the horizontal radius is less than vertical radius, so our ellipse will be a vertical ellipse. The center of our ellipse is at origin (0,0).
Upon graphing our ellipse, we will our required graph as:
