Compute the diameter of a square link subjected to a compres- sive load of 27,000 lbs. Modulus of elasticity 30 x 106 psi. Proportionality limit 38,000 psi, working stress - 7000 psi, length of the link 55 in.

Respuesta :

Answer:

The diameter of a square link is 0.0233 inch.

Explanation:

Given that,

Load = 27000 lbs

Modulus of elasticity [tex]E= 30\times10^{6}\ psi[/tex]

Working stress [tex]\sigma=7000\ psi[/tex]

length l = 55 in

We need to calculate the diameter of a square link

Using formula of stress

[tex] \sigma=\dfrac{Force}{Area}[/tex]

[tex]7000=\dfrac{27000}{\pi\times d\times L}[/tex]

Put the value into the formula

[tex]d=\dfrac{27000}{7000\times3.14\times55}[/tex]

[tex]d=0.0223\ inch[/tex]

Hence, The diameter of a square link is 0.0233 inch.