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A ball is released at a height of 27 inches to roll inside a half-cylinder. It rolls
to a height of 9 inches on the other side of the cylinder on roll 1. Each time it
rolls up a side of the cylinder, the ball reaches a point th
high as it
had reached on the other side.
This explicit formula models the height of the ball, in inches, the nth time it
rolls up a side of the cylinder.
How high does the ball roll on its 4th time up the cylinder's side?

A ball is released at a height of 27 inches to roll inside a halfcylinder It rolls to a height of 9 inches on the other side of the cylinder on roll 1 Each time class=

Respuesta :

calculista

Answer:

[tex]\frac{1}{3}\ in[/tex]

Step-by-step explanation:

we have

[tex]a(n)=9(\frac{1}{3})^{n-1}[/tex]

For n=4

substitute

[tex]a(4)=9(\frac{1}{3})^{4-1}[/tex]

[tex]a(4)=9(\frac{1}{3})^{3}[/tex]

[tex]a(4)=9(\frac{1}{27})[/tex]

[tex]a(4)=\frac{1}{3}\ in[/tex]

mysongplaylist2000s

Answer:

1/3

Step-by-step explanation:

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