Answer:
Maximum distance of image from mirror is equal to focal length of the mirror
Explanation:
As we know by the equation of mirror we have
[tex]\frac{1}{d_i} + \frac{1}{d_o} = \frac{1}{f}[/tex]
here we know for convex mirror
object position is always negative as it will be placed behind the mirror always
while the focal length of the convex mirror is always taken positive
So here we have
[tex]\frac{1}{d_i} + \frac{1}{-d_o} = \frac{1}{f}[/tex]
[tex]\frac{1}{d_i} = \frac{1}{d_o} + \frac{1}{f}[/tex]
so here maximum value of image distance is equal to focal length of the mirror
