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A very light ideal spring having a spring constant (force constant) of 8.2 N/cm is used to lift a 2.2-kg tool with an upward acceleration of 3.25 m/s2. If the spring has negligible length when it us not stretched, how long is it while it is pulling the tool upward?

Respuesta :

Answer:

x = 3.5 cm

Explanation:

When spring is used as a lift tool

so the mass suspended on it will have spring force on it

So as per the force equation of mass we can say

[tex]F_{net} = ma[/tex]

now net force on the mass is

[tex]F_{net} = kx - mg[/tex]

[tex]F_{net} = kx - mg = ma[/tex]

here we have

[tex]kx = mg + ma[/tex]

now we have

[tex]x = \frac{mg + ma}{k}[/tex]

[tex]x = \frac{2.2(9.8) + 2.2(3.25)}{8.2}[/tex]

[tex]x = 3.5 cm[/tex]