Answer:
The momentum of the two-block system is 18 kg-m/s
Explanation:
It is given that,
Mass of block A, [tex]m_A=4\ kg[/tex]
Mass of block B, [tex]m_B=6\ kg[/tex]
Velocity of block A, [tex]v_A=3\ m/s[/tex]
Velocity of block B, [tex]v_B=-5\ m/s[/tex] (it is moving in opposite direction)
We need to find the momentum of two block system. It is given by the product of mass and velocity for both blocks i.e.
[tex]p=m_Av_A+m_Bv_B[/tex]
[tex]p=4\ kg\times 3\ m/s+6\ kg\times (-5\ m/s)[/tex]
p = -18 kg-m/s
So, the momentum of two block system is 18 kg-m/s. Hence, this is the required solution.
