Answer:5
[tex]7.26\times 10^{-6}[/tex]μM is the initial concentration of the substrate, [S], used in the reaction.
Explanation:
Michaelis–Menten 's equation:
[tex]v=V_{max}\times \frac{[S]}{(K_m+[S])}=k_{cat}[E_o]\times \frac{[S]}{(K_m+[S])}[/tex]
[tex]V_{max}=k_{cat}[E_o][/tex]
v = rate of formation of products =[tex]1.07\times 10^{-6}[/tex] μM/s
[S] = Concatenation of substrate = ?
[tex][K_m][/tex] = Michaelis constant = 15.0 μM
[tex]V_{max}[/tex] = Maximum rate achieved
[tex]k_{cat}[/tex] = Catalytic rate of the system = 221 [tex]s^{-1}[/tex]
[tex][E_o][/tex] = Initial concentration of enzyme. =0.0100 μM
On substituting all the given values:
[tex][S]=7.26\times 10^{-6}[/tex]μM
[tex]7.26\times 10^{-6}[/tex]μM is the initial concentration of the substrate, [S], used in the reaction.
