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A battery with an emf of 12 V and an internal resistance of 1 Ω is used to charge a battery with an emfof 10 V and an internal resistance of 1 Ω. The current in the circuit is : A) 2 A B) 1 A C) 4A D) 11A E) 22 A

Respuesta :

Answer:

Option B

Explanation:

The net emf in the circuit

E = 12 - 10 = 2 V

Total effective resistance,

r = 1 + 1 = 2 ohm

By using Ohm's law

E = I × R

I = 2 / 2 = 1 A

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