Answer:
[tex]L = 9.42 kg m^2/s[/tex]
Explanation:
Angular speed of the cylinder is given as
[tex]f = 1500 rpm[/tex]
[tex]f = 1500 round/60 s[/tex]
[tex]\omega = 2\pi f[/tex]
[tex]\omega = 2\pi(25) = 50 \pi[/tex]
now moment of inertia of the cylinder is given as
[tex]I = \frac{1}{2}mR^2[/tex]
[tex]I = \frac{1}{2}(3)(0.2)^2[/tex]
[tex]I = 0.06 kg m^2[/tex]
now we have
[tex]L = I\omega[/tex]
[tex]L = (0.06)(50\pi)[/tex]
[tex]L = 9.42 kg m^2/s[/tex]
