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A pump lifts water from a lake to a large tank 20 m above the lake. How much work against gravity does the pump do as it transfers 5.0 m^3 if the density is ?=1000kg/m^3?

Respuesta :

MathPhys

Answer:

980 kJ

Explanation:

Work = change in energy

W = mgh

W = (1000 kg/m³ × 5.0 m³) (9.8 m/s²) (20 m)

W = 980,000 J

W = 980 kJ

The pump does 980 kJ of work.

Eduard22sly

The work done by the pump against gravity in transfering 5 m³ of water to a tank 20 m above the lake is 980000 J

We'll begin by calculating the mass of the water. This can be obtained as follow:

Volume of water = 5 m³

Density of water = 1000 Kg/m³

Mass of water =?

Mass = Density × Volume

Mass of water = 1000 × 5

Mass of water = 5000 Kg

  • Finally, we shall determine the work done by the pump. This can be obtained as illustrated below:

Mass of water (m) = 5000 Kg

Height (h) = 20 m

Acceleration due to gravity (g) = 9.8 m/s²

Work done = ?

Work done = mgh

Work done = 5000 × 9.8 × 20

Work done = 980000 J

Thus, the work done by the pump is 980000 J

Learn more: https://brainly.com/question/16976412

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