Answer:
a) 0.0483 mol
b) 232 °C
Explanation:
Ideal gas law:
PV = nRT
where P is absolute pressure,
V is volume,
n is number of moles,
R is universal gas constant,
and T is absolute temperature.
a) Given:
P = 1.20×10⁵ Pa
V = 1.00 L = 1.00×10⁻³ m³
T = 25.8 °C = 298.95 K
PV = nRT
(1.20×10⁵ Pa) (1.00×10⁻³ m³) = n (8.314 m³ Pa / mol / K) (298.95 K)
n = 0.0483 mol
b) Given:
P = 1.013×10⁵ Pa
V = 2.00 L = 2.00×10⁻³ m³
n = 0.0483 mol
PV = nRT
(1.013×10⁵ Pa) (2.00×10⁻³ m³) = (0.0483 mol) (8.314 m³ Pa / mol / K) T
T = 505.73 K
T = 232 °C
