contestada

When an object is oscillating in simple harmonic motion in the vertical direction, its maximum speed occurs when the object A) is at its highest point B) is at its lowest point C) is at the equilibrium point D) has the maximum net force exerted on it E) has a position equal to its amplitude

Respuesta :

Answer:

C) is at the equilibrium point

Explanation:

As we know that the equation of displacement of SHM executing object is given as

[tex]x = A sin(\omega t + \phi)[/tex]

now for velocity of the particle we will have

[tex]v = \frac{dx}{dt}[/tex]

now we will have

[tex]v = A\omega cos(\omega t + \phi)[/tex]

now if velocity is maximum then we will have

[tex]cos(\omega t + \phi) = \pm 1[/tex]

so at this situation we will have

[tex](\omega t + \phi) = N\pi[/tex]

now at this angle the value of

[tex]sin(\omega t + \phi) = 0[/tex]

so the position must be mean position at which the particle is at equilibrium position

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