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A 13.1 μF capacitor is connected through a 853 kΩ resistor to a constant potential difference of 64 V. Compute the charge on the capacitor at 14 s after the connections are made. (Give your answer in decimal using micro C (μC) as unit)

Respuesta :

Answer:

[tex]q = 598.9 \mu C[/tex]

Explanation:

As we know that when an uncharged capacitor is connected through a voltage source then the charge on the plates of capacitor will increase with time.

It is given by the equation

[tex]q = CV(1 - e^{-\frac{t}{RC}})[/tex]

here we know that

[tex]C = 13.1 \mu F[/tex]

[tex]R = 853 k ohm[/tex]

V = 64 volts

now we have

[tex]q = (13.1 \mu F)(64) ( 1 - e^{-\frac{14}{(853\times 10^3)(13.1 \times 10^{-6})}})[/tex]

[tex]q = 598.9 \mu C[/tex]

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