Answer:
Net force, F = 7 N
Explanation:
It is given that,
Initial kinetic energy of the car, [tex]K_i=3\ J[/tex]
Final kinetic energy of the car, [tex]K_f=10\ J[/tex]
Distance, d = 1 m
We need to find the average net force on the car during this interval. It is given by using the work energy theorem as :
[tex]W=\Delta K[/tex]
[tex]W=K_f-K_i[/tex]
Also, W = F.d d = distance and F = net force
[tex]F.d=K_f-K_i[/tex]
[tex]F=\dfrac{K_f-K_i}{d}[/tex]
[tex]F=\dfrac{10\ J-3\ J}{1\ m}[/tex]
F = 7 Newton
So, the average net force on the car during this interval is 7 newton. Hence, this is the required solution.
