Answer:
Velocity is 34.42 m/s at an angle of 56.91° below horizontal
Speed is 34.42 m/s
Explanation:
Velocity = 20.0 m/s at an angle of 30° below horizontal
Vertical velocity = 20 sin 20 = 6.84 m/s downward.
Horizontal velocity = 20 cos 20 = 18.79 m/s towards right.
Let us consider the vertical motion of ball we have equation of motion
v² = u² + 2as
We need to find v, u = 6.84 m/s, a = 9.81 m/s² and s = 40 m
Substituting
v² = 6.84² + 2 x 9.81 x 40 = 831.59
v = 28.84 m/s
So on reaching ground velocity of ball is
Vertical velocity = 28.84 m/s downward.
Horizontal velocity = 18.79 m/s towards right.
Velocity
[tex]v=\sqrt{28.84^2+18.79^2}=34.42m/s[/tex]
[tex]tan\theta =\frac{28.84}{18.79}\\\\\theta =56.91^0[/tex]
So velocity is 34.42 m/s at an angle of 56.91° below horizontal
Speed is 34.42 m/s
