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A wire of a certain length is carrying a current of 2.0 A. It is placed at an angle of 60° with respect to a magnetic field of strength 0.20 T. If the wire experiences a force of 0.40 N, what is the length of the wire?

Respuesta :

Answer:

1.2 m

Explanation:

i = current flowing through the wire = 2.0 A

θ = Angle between the length of wire and magnetic field = 60° deg

B = magnitude of magnetic field = 0.20 T

L = Length of the wire = ?

F = Magnitude of magnetic force experienced by the wire

Magnetic force on the wire is given as

F = i B L Sinθ

0.40 = (2.0) (0.20) L Sin60

L = 1.2 m

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