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A player gets to throw 4 darts at the target shown. Assuming the player will always hit the target, the probability of hitting an odd number three times is times more than the probability of hitting an even number three times.

HELP ME A player gets to throw 4 darts at the target shown Assuming the player will always hit the target the probability of hitting an odd number three times i class=

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Answer:

The probability of hitting an odd number three times is 3.375 times more than the probability of hitting an even number three times..

Step-by-step explanation:

Probability of hitting an odd number = 3/5

Probability of hitting an odd number = 2/5

Probability of hitting an odd number three times = (3/5)^3

Probability of hitting an odd number three times = (2/5)^3

Now divide (3/5)^3 by  (2/5)^3 we get:

(3/5)^3 / (2/5)^3

(3)^3/(2)^3

27/8 = 3.375

The probability of hitting an odd number three times is 3.375 times more than the probability of hitting an even number three times..

Answer:

The answer is  1.5

Step-by-step explanation:

probability for even number 2/5

probability for odd number 3/5

Probability for 4 darts

odd: (3/5)4     Even: (2/5)4

divide the odd by the even probability, and you get 1.5